Final answer:
To find the volume of a 0.360 M barium acetate solution containing 100 g of the solute, we first calculate the number of moles of barium acetate and then divide by the molarity. The final answer is 1.087 L.
Step-by-step explanation:
We need to calculate the volume of a 0.360 mol/l barium acetate solution that contains 100 g of barium acetate. First, we must find the molar mass of barium acetate, Ba(C₂H₃O₂)₂, which is 137.33 g/mol for barium (Ba) plus 2x59.04 g/mol for each acetate ion (C₂H₃O₂), totaling approximately 255.41 g/mol.
To find the number of moles of barium acetate:
Next, use the molarity of the solution to calculate the volume that contains these moles:
Therefore, the volume of the barium acetate solution needed to contain 100 g of barium acetate is 1.087 L, rounded to three significant digits.