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Calculate the total energy contained in the electric field of a solid sphere of radius 95.3 mm and charge 18.1μC uniformly distributed throughout its volume. (Please provide your answer in J to 2 decimal places)

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Final answer:

The total energy contained in the electric field of a solid sphere can be calculated using the formula E = (3/5)*(k * Q^2)/R, where E is the electric field energy, k is the electrostatic constant, Q is the charge, and R is the radius of the sphere.

Step-by-step explanation:

To calculate the total energy contained in the electric field of a solid sphere, we can use the formula:

E = (3/5)*(k * Q^2)/R

Where:

  • E is the electric field energy
  • k is the electrostatic constant (8.99 x 10^9 Nm^2/C^2)
  • Q is the charge (18.1µC)
  • R is the radius of the sphere (95.3 mm)

Plugging in the values, we get:

E = (3/5) * (8.99 x 10^9 Nm^2/C^2) * (18.1 x 10^-6 C)^2 / (95.3 x 10^-3 m)

Calculating this, we find that the total energy contained in the electric field of the solid sphere is approximately 2.12 J.

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