Final answer:
A 60.0 g sample of camphor (C10H16O) contains 3.78 x 10^25 hydrogen atoms, calculated by finding the number of moles in the sample and multiplying by Avogadro's number and the number of hydrogen atoms per molecule.
Step-by-step explanation:
To calculate the number of hydrogen atoms in a 60.0 g sample of camphor (C10H16O), we first need to determine the number of moles of camphor in the sample. The molecular weight of camphor is 152.23 g/mol (C10H16O = 10*12.01 g/mol + 16*1.01 g/mol + 1*16.00 g/mol). Using the mass of the sample and the molecular weight, we find:
Number of moles of camphor = 60.0 g / 152.23 g/mol = 0.394 moles of camphor.
Since each molecule of camphor contains 16 hydrogen atoms, the total number of hydrogen atoms in the sample is:
Number of hydrogen atoms = 0.394 moles * 6.022 x 1023 atoms/mole * 16 atoms/molecule = 3.78 x 1025 hydrogen atoms.
Therefore, a 60.0 g sample of camphor contains 3.78 x 1025 hydrogen atoms.