Question

Refrigerant-134a at 400 psia has a specific volume of 0.1384 flbm. The gas constant, the critical pressure, and the critical temperature of refrigerant-134a are R=010517 psia Albm R. To=673.6 R. and Per-5887 psla. Use data from the steam tables. Determine the temperature of the refrigerant based on the refrigerant tables.

Answer 1

Refrigerant-134a at 400 psia has a specific volume of 0.1384 flbm, the temperature of the refrigerant is 529.31 °R.

Step-by-step explanation:

The temperature of the refrigerant can be determined using the ideal gas law equation:

PV = nRT

Where

P is the pressure

V is the specific volume

n is the number of moles

R is the gas constant

T is the temperature.

Given that the pressure is 400 psia and the specific volume is 0.1384 flbm

We can rearrange the equation and solve for the temperature:

T = PV / (nR)

Substituting the given values, we have:

T = (400 psia) * (0.1384 flbm) / ((1 mol) * (0.010517 psia ft^3 / lbm °R))

T = 529.31 °R

Therefore the temperature of the refrigerant based on the given values is 529.31 °R.