Question

The electric field strength is 2.50×10^4 N/C inside a parallel-plate capacitor with a 0.700 mm spacing. An electron is released from rest at the negative plate. Calculate the acceleration of the electron.

Answer 1

The acceleration of the electron is approximately 4.37 × 10^14 m/s^2.

Step-by-step explanation:

To calculate the acceleration of the electron, we can use the equation F = qE, where F is the force, q is the charge of the electron, and E is the electric field strength. The force experienced by the electron is given by F = ma, where m is the mass of the electron and a is the acceleration. Setting these two equations equal to each other, we have ma = qE. Since we are solving for acceleration, we can rearrange the equation to get a = qE/m. Plugging in the values, we have a = (1.6 × 10^-19 C)(2.50 × 10^4 N/C) / (9.11 × 10^-31 kg). Calculating this gives us an acceleration of approximately 4.37 × 10^14 m/s^2.