Question

A flat sheet of paper with an area of 0.370 m^2 is oriented so that the normal to the sheet is at an angle of 67 degrees to a uniform electric field of magnitude 20 N/C. Determine the electric flux through the sheet.

Answer 1

The electric flux through the sheet of paper is approximately 7.6 Nm^2/C.

Step-by-step explanation:

The electric flux through a flat sheet of paper can be calculated using the formula: Electric Flux = Electric Field * Area * cos(theta), where theta is the angle between the normal to the sheet and the electric field. In this case, the electric field has a magnitude of 20 N/C and the area of the sheet is 0.370 m^2. The angle between the normal to the sheet and the electric field is 67 degrees. Plugging these values into the formula, we get:

Electric Flux = 20 N/C * 0.370 m^2 * cos(67°)

Simplifying the cosine, we find:

Electric Flux ≈ 7.6 Nm^2/C