she can afford to rent the car for a maximum of 4 days while staying within her budget.
Let x be the number of days Alyssa plans to rent the car. The total cost C for renting the car for x days and driving 100 miles is given by the equation:
![\[ C = 37.50x + 0.05 * 100 * x \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/s4jvplhw3g6xt3nhc8qxui09c6d4s33nv4.png)
However, Alyssa has at most $200 to spend, so we can write the inequality:
![\[ 37.50x + 0.05 * 100 * x \leq 200 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/k9q9024ggiavotlk0xwr3n0d4dupvt6177.png)
Now, let's solve for x:
![\[ 37.50x + 5x \leq 200 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/550hui380de8xhlmkb6c52u6ryzq0ifvw5.png)
Combine like terms:
![\[ 42.50x \leq 200 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/c1zjckb26ph2utk8njv6obqbrkbhw611is.png)
Divide both sides by 42.50:
![\[ x \leq (200)/(42.50) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/69mbtvu9uidvtkutcjjvot7jv5cjulrc22.png)
Simplify the right side:
![\[ x \leq 4.705 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/x9sezn2hyvhf37et8y0xplyxz5ur7m650c.png)
Since Alyssa cannot rent a fraction of a day, she must round down to the nearest whole number. Therefore, she can afford to rent the car for a maximum of 4 days while staying within her budget.
The probable question may be:
A rental car company charges $37.50 per day to rent a car and $0.05 for every mile driven. Alyssa wants to rent a car, knowing that: She plans to drive 100 miles. She has at most $200 to spend. Write and solve an inequality which can be used to determine x, the number of days Alyssa can afford to rent while staying within her budget.