Question

What is the molarity of a solution containing 15 mL and 0.00358 mol of HCl?

a) 2.39 M
b) 0.239 M
c) 0.0239 M

Answer 1

The molarity of a solution containing 0.00358 mol of HCl in 15 mL is 0.239 M, which is calculated using the formula: molarity = moles of solute / liters of solution.

Step-by-step explanation:

Steps to Calculate Molarity

To calculate the molarity of a solution, you need to divide the number of moles of the solute by the volume of the solution in liters. The formula for molarity (M) is M = moles of solute / liters of solution.

Answer to the Student's Question

The molarity of a solution containing 0.00358 mol of HCl in 15 mL (0.015 L) is calculated as follows:

molarity = 0.00358 mol / 0.015 L = 0.239 M

General Example

Consider a solution with 0.614 mol of HCl in 1.56 L of solution. The molarity is calculated by dividing the number of moles by the liters:

molarity = 0.614 mol HCl / 1.56L solution = 0.393 M.