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A wedding ring is a circle with a radius of 1.0 cm. If the normal to the surface bounded by the ring is parallel to the Earth’s electric field of 150 N/C, what is the electric flux through the ring?

User Naoufal
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Final answer:

The electric flux through the ring can be calculated using the formula φ = E * A * cos(θ), where E is the electric field, A is the area of the ring, and θ is the angle between the electric field and the normal to the surface of the ring. In this case, the angle is 0°, so the electric flux is E * A. Substituting the given values gives a flux of 150π N·cm^2/C.

Step-by-step explanation:

The electric flux through the ring can be calculated using the formula:

φ = E * A * cos(θ)

Where φ is the electric flux, E is the electric field, A is the area of the ring, and θ is the angle between the electric field and the normal to the surface of the ring.

In this case, the normal to the surface of the ring is parallel to the Earth's electric field, so the angle between the electric field and the normal is 0°. Therefore, the cosine of 0° is 1, and the electric flux through the ring is E * A.

Since the radius of the ring is 1.0 cm, the area of the ring is π * (1.0 cm)^2 = π cm^2. The electric field is given to be 150 N/C. Substituting these values into the formula gives:

φ = (150 N/C) * (π cm^2) = 150π N·cm^2/C

User Mdexp
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