Question

Consider two bulbs containing argon (left) and oxy gen (right) gases. After the stopcock is opened, the pressure of the combined gases is 1.08 atm. Calculate the volume of the right bulb. The temper- ature is kept at 20°C. Assume ideal behavior.

Answer 1

Consider two bulbs containing argon (left) and oxy gen (right) gases, the volume of the right bulb is 5.79 times the number of moles of gases.

Step-by-step explanation:

To calculate the volume of the right bulb, we can use the combined gas law equation: PV = nRT.

Where

P is the pressure

V is the volume

n is the number of moles of gas

R is the ideal gas constant

T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin. 20°C + 273 = 293 K.

Since the gases are combined, we can assume that the number of moles of the two gases is the same. Let's call this value x.

Using the given pressure of 1.08 atm and the temperature of 293 K, we can solve for the volume:

V = (nRT) / P = (2x)(0.0821 L·atm/mol·K)(293 K) / 1.08 atm = 5.79x L

Therefore, the volume of the right bulb is 5.79 times the number of moles of gases.