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A piano tuner stretches a steel piano wire with a tension of 765 N. The steel wire has a length of 0.700m and a mass of 5.25g.

A. What is the frequency f₁ of the string's fundamental mode of vibration?

User Tsang
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1 Answer

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Final answer:

To find the frequency of the string's fundamental mode of vibration, use the formula f₁ = (1/2L) * √(T/μ). Plugging in the given values, the frequency is approximately 127.8 Hz.

Step-by-step explanation:

To find the frequency of the string's fundamental mode of vibration, we can use the formula:

f₁ = (1/2L) * √(T/μ)

Where f₁ is the frequency, L is the length of the string, T is the tension in the string, and μ is the linear mass density of the string.

Plugging in the given values, we have:

f₁ = (1/2 * 0.700m) * √(765N / (5.25g/0.700m) * 9.8m/s²)

Convert the mass from grams to kilograms:

f₁ = (1/2 * 0.700m) * √(765N / (0.00525kg/0.700m) * 9.8m/s²)

Simplify the equation:

f₁ = (1/2 * 0.700m) * √(981600N / 0.00735kg)

f₁ = 350N * √133333.33

Calculate the square root:

f₁ ≈ 350N * 365.16 ≈ 127.8 Hz

Therefore, the frequency f₁ of the string's fundamental mode of vibration is approximately 127.8 Hz.

User Wynona
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