Question

A stream of humid air containing 1.50 mole% H20(v) and the balance dry air is to be humidified to a water content of 10.0 mole% H2O. For this purpose, liquid water is fed through a flowmeter and evaporated into the air stream. The flowmeter reading, R, is 95. The only available calibration data for the flowmeter are two points scribbled on a sheet of paper, indicating that readings R15 and R 50 correspond to flow rates V 40.0 ft3/h and V 96.9 ft3/h, respectively. Assuming that the process is working as intended, draw and label the flowchart.

Answer 1

To calculate the mass of water that has passed into the air when the room becomes saturated with water vapor, use the ideal gas law equation and molar mass of water.

Step-by-step explanation:

Given the initial equilibrium vapor pressure of water at 19ºC as 0.02168 atm and the volume of the room as 180 m³, we can calculate the mass of water that has passed into the air when the room becomes saturated with water vapor.

The mass of water vapor in the air can be determined using the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

By rearranging the equation to solve for n, we can find the number of moles of water vapor in the air. Multiplying the number of moles by the molar mass of water, we can calculate the mass of water that has passed into the air.