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What is the intensity of an electromagnetic wave with a peak electric field strength of 231 v/m?

User Demarcmj
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Final answer:

The intensity of the electromagnetic wave with a peak electric field strength of 231 V/m is approximately 2670 W/m^2.

Step-by-step explanation:

The intensity of an electromagnetic wave can be calculated using the equation:

I = (E0)2/(2c)

Where:

  • I is the intensity of the wave
  • E0 is the peak electric field strength
  • c is the speed of light in a vacuum (~3.00 x 108 m/s)

Using the given peak electric field strength of 231 V/m, we can substitute the values into the equation:

I = (2312) / (2 * 3.00 x 108)

Simplifying the equation, we get:

I ≈ 2670 W/m2

Therefore, the intensity of the electromagnetic wave is approximately 2670 W/m2.

User Atrag
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