Question

Consider a second-order reaction, products, with a half-life of 22.5 s. Calculate the rate constant when the initial reactant concentration is 0.250 M.

a-1.95 x 10^-2 M^-1s^-1
b-9.75 10^-3 M^-1s^-1
c- 0.178 M^-1s^-1
d-0.567 M^-1s^-1

Answer 1

The rate constant for the second-order reaction is 0.178 M^-1s^-1.

Step-by-step explanation:

The rate constant for a second-order reaction can be calculated using the equation:

k = (1/t1/2) * (1/[A0])

where t1/2 is the half-life of the reaction and [A0] is the initial reactant concentration. In this case, the half-life is given as 22.5 s and the initial reactant concentration is 0.250 M. Plugging these values into the equation, we get:

k = (1/22.5) * (1/0.250) = 0.178 M-1s-1

Therefore, the rate constant for the reaction is 0.178 M-1s-1.