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At what points does the curve r(t) = ti + (4t + t²)k intersect the paraboloid z = x² + y²?

User Jfadich
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1 Answer

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Final answer:

To find the points of intersection between the curve r(t) = ti + (4t + t²)k and the paraboloid z = x² + y², substitute the values of x, y, and z from the curve equation into the equation of the paraboloid.

Step-by-step explanation:

To find the points of intersection between the curve r(t) = ti + (4t + t²)k and the paraboloid z = x² + y², we need to substitute the values of x, y, and z from the curve equation into the equation of the paraboloid.

Given that r(t) = ti + (4t + t²)k, we can find x and y by equating the coefficients of the i and j unit vectors, respectively. So, x = t and y = 4t + t².

Substituting these values into the equation of the paraboloid, we get z = (t)² + (4t + t²)². Simplifying this equation will give us the points of intersection.

To determine at what points the curve r(t) = ti + (4t + t²)k intersects the paraboloid z = x² + y², we need to find the values of t for which the z-coordinate of the curve matches the z-coordinate of the paraboloid.

The curve given has no j (y) component, which implies that y = 0. The x-coordinate of the curve is t, and since y is zero, the z-coordinate of the curve is given as 4t + t².

Now, we will equate the z-coordinate of the curve to the z-value in the paraboloid equation:

4t + t² = t² + 0²

4t + t² = t²

4t = 0

From the last equation, it is clear that t = 0. Thus, the curve intersects the paraboloid at the origin, which is the only intersection point.

User Uingtea
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