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If |v|= 2, |w|= 3, and the angle between v and w is π/3, find | v - 2w|.

User Serzhas
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1 Answer

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Final answer:

To find | v - 2w |, we need to subtract 2w from v and then find the magnitude of the resulting vector. Given that |v| = 2, |w| = 3, and the angle between v and w is π/3, the magnitude of v - 2w is approximately 4.73.

Step-by-step explanation:

To find | v - 2w |, we need to subtract 2w from v and then find the magnitude of the resulting vector.

Given that |v| = 2, |w| = 3, and the angle between v and w is π/3, we can find the components of v and w as follows:

v = 2cos(π/3)i + 2sin(π/3)j

w = 3cos(0)i + 3sin(0)j

Substituting the values, we get:

v - 2w = (2cos(π/3) - 2 * 3cos(0))i + (2sin(π/3) - 2 * 3sin(0))j

Simplifying the expression:

v - 2w = (2 * 1/2 - 2 * 3 * 1)i + (2 * √3/2 - 2 * 3 * 0)j

Finally, the magnitude of v - 2w is:

| v - 2w | = √((2 * 1/2 - 2 * 3 * 1)^2 + (2 * √3/2 - 2 * 3 * 0)^2)

Calculating the expression, we get:

| v - 2w | ≈ 4.73

User Jeebface
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