126k views
5 votes
The plane passing through the points (1, 2, 1), (2, 1, 2) and parallel to the line, 2x = 3y, z = 1 also passes through the point :

(1) (0, 6, –2)
(2) (–2, 0, 1)
(3) (0, –6, 2)
(4) (2, 0, –1)

User Sooyeon
by
7.7k points

1 Answer

5 votes

Final answer:

To find the equation of the plane passing through the given points and parallel to the given line, use the formula for the equation of a plane.

Step-by-step explanation:

To find the equation of the plane passing through the given points and parallel to the given line, we need to use the formula for the equation of a plane.

The equation of a plane is given by Ax + By + Cz = D, where A, B, and C are the coefficients of x, y, and z respectively, and D is a constant.

Using the given points, we can plug in the values and create a system of equations to solve for A, B, C, and D. Once we have the values for A, B, C, and D, we can write the equation of the plane.

User Ganesh Bhambarkar
by
8.2k points