Final answer:
The osmolarity of a solution containing 3 M MgCl2 and 2 M glucose is 5 osM.
Step-by-step explanation:
The osmolarity of a solution can be determined by summing the osmolarities of each solute present. To calculate the osmolarity, we need to consider the number of particles each solute will generate when it dissolves. In this case, MgCl2 will dissociate into three particles (1 Mg²+ and 2 Cl-) while glucose will remain as a non-electrolyte and will not dissociate. Therefore, the osmolarity of the solution will be:
3 M MgCl2 = 3 osM (1 Mg²+ and 2 Cl-)
2 M glucose = 2 osM
Total osmolarity = 3 osM + 2 osM = 5 osM