Question

How many molecules of CH4 are in 24.1 g of this compound?

Answer 1

1) find molar mass of CH₄

`=12.01+4(1.01)\\\\=16.05\ g/mol`

2) determine moles of CH₄

`=24.1g\ CH_(4)\ x\ (1\ mol\ CH_(4))/(16.05g\ CH_(4))\\\\=1.501557632\ mol\ CH_(4)`

3) multiply by avogadro's number

`=1.501557632\ mol\ CH_(4)\ x\ (6.022\ x\ 10^(23)\ molecules\ CH_(4))/(1\ mol\ CH_(4)) \\\\=9.04238006\ x\ 10^(23)\\\\=9.04\ x\ 10^(23)\ molecules\ CH_(4)`