Final answer:
To find the probability of an AA bb Cc dd offspring from a cross between AA Bb Cc Dd and Aa Bb cc dd individuals, use the probability method by multiplying the individual gene probabilities, resulting in a final probability of 3.125%.
Step-by-step explanation:
In a cross between individuals with genotypes AA Bb Cc Dd and Aa Bb cc dd, instead of making a large Punnett square, you can use the probability method to calculate the probability of an offspring with a given genotype. For the offspring to be AA bb Cc dd, we consider each gene independently:
- For the A gene, since one parent is AA and the other is Aa, the offspring has a 100% chance of receiving at least one A allele. Thus, the probability of an AA genotype is 50% (from the Aa parent).
- For the B gene, both parents are Bb, so the probability of bb offspring is 25%.
- For the C gene, one parent is Cc,and the other is cc, so the probability of Cc offspring is 50%.
- For the D gene, since one parent is Dd and the other is dd, the offspring has a 50% chance of being Dd and 50% chance of being dd.
To find the overall probability of the AA bb Cc dd genotype, you multiply the individual probabilities: 0.5 (AA) x 0.25 (bb) x 0.5 (Cc) x 0.5 (dd) = 0.03125 or 3.125%.