Question

A bag contains 10 red balls, 8 green balls, and 6 blue balls. 2 balls are drawn at random at the bag. What is the probability that both balls are red?​

Answer 1

41.67%

Explanation:

10+8+6= 24

10/24

First, you need to calculate your grade in percentages. The total answers count 24 - it's 100%, so we to get a 1% value, divide 24 by 100 to get 0.24. Next, calculate the percentage of 10: divide 10 by 1% value (0.24), and you get 41.67% - it's your percentage grade

Answer 2

Assuming every single ball has an equal chance of being drawn, then if B is the probability of drawing a blue ball and R is the probability of drawing a red ball:

B + R = 1,

since either a red or blue ball will be drawn. Since each ball has an equal chance of being drawn:

16 p = 1, or

p = 1/16

where p is the chance to draw a single ball. Since there are 10 red balls, there are ten independent and different ways to draw a red ball, which means that

R = 10 p = 10/16 = 5/8.

You can either apply the first equation to find that

B = 1 - R = 3/8

or state directly that

B = 6 p = 6/16 = 3/8

since there are six independent and different ways to draw a blue ball from the bag.