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Flame hazard class example and description

A) Propane - Intense heat and radiant energy
B) Gasoline - Spontaneous combustion risk
C) Acetylene - Slow-burning sustained flames
D) Methane - Low ignition temperature

User JoJo
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Final answer:

The combustion of propane and methane are chemical reactions that release heat and produce carbon dioxide and water. Propane's combustion is represented by a balanced chemical equation involving sufficient oxygen, while methane, prevalent in natural gas, combusts easily releasing significant heat energy.

Step-by-step explanation:

The flame hazard classes of various fuels relate to the specific dangers associated with their combustion. When balancing a combustion equation, one must ensure a proper stoichiometric ratio of reactants to products is achieved. For propane (C3H8), the balanced equation for complete combustion is C3H8(l) + 5O2(g) → 3CO2(g) + 4H2O(l), demonstrating the production of carbon dioxide and water upon combustion.

Methane (CH4) burns easily, which is one reason it's used widely as a natural gas fuel. Its combustion is represented by the equation CH4(g) + 2O2(g) → CO2(g) + 2H2O(l), releasing large amounts of heat energy. Such combustion reactions are exothermic, releasing energy that can be quite intense, depending on the hydrocarbon.

User Rishimaharaj
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