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On a car trip, the time of trip varies inversely with the speed traveled. One car drove 81 mph and it took them 55 minutes. If a different car made the same trip at a speed of 45 mph, how many minutes would the trip take?

User AGO
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Final answer:

The time for a car trip is inversely related to the speed traveled. Using an inverse proportion formula, we can find the time for a car traveling at a different speed. In this case, if a car drove 81 mph and took 55 minutes, a different car traveling at 45 mph would take approximately 99.67 minutes for the trip.

Step-by-step explanation:

The time of a car trip and the speed traveled are inversely related. In this case, if one car drove 81 mph and took 55 minutes, we can use the inverse proportion formula to find the time for a different car traveling at 45 mph:

Speed1 × Time1 = Speed2 × Time2

81 mph × 55 minutes = 45 mph × Time2

Solving for Time2, we have:

Time2 = (81 mph × 55 minutes) ÷ 45 mph

Time2 ≈ 99.67 minutes

Therefore, if the different car travels at 45 mph, the trip would take approximately 99.67 minutes.

User Johnwards
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