Final answer:
To have $10,000 in ten years in a bank account with 10% interest compounded annually, you would need to deposit approximately $3,855.03.
Step-by-step explanation:
Calculating the Initial Deposit for Compound Interest
To determine how much money you would need to deposit into a bank account that pays 10% interest compounded annually in order to have $10,000 in ten years, you use the formula for compound interest:
P = A / (1 + r/n)^(nt)
Where:
- P is the principal amount (initial deposit)
- A is the future value of the investment/loan, including interest
- r is the annual interest rate (decimal)
- n is the number of times that interest is compounded per year
- t is the number of years the money is invested or borrowed for
In this case, since the interest is compounded annually, n = 1. Therefore, the formula simplifies to:
P = A / (1 + r)^t
Plugging in the known values:
P = $10,000 / (1 + 0.10)^10 = $10,000 / (1.10)^10
Calculating the denominator we get:
P = $10,000 / 2.59374
And finally, solving for P gives:
P = $3,855.03
Therefore, you would need to deposit approximately $3,855.03 into the bank account.