Final answer:
To make a 4 Osm solution, 1368 g of sucrose, which has a molecular weight of 342 g/mol, is needed to be dissolved in 1 liter of water. The correct option is B.
Step-by-step explanation:
The question is asking how many grams of sucrose you need to dissolve in 1 liter of water to create a 4 Osmolar (Osm) solution. The molecular weight of sucrose is 342 g/mol.
To find the mass of sucrose required for a 4 Osm solution in 1 liter of water, we need to use the formula for osmolarity which is Osmolarity = moles of solute / volume of solution in liters. Since 1 Osm = 1 mol/L, for a 4 Osm solution, we need 4 moles of sucrose. Therefore, we calculate the grams of sucrose required using the molecular weight:
4 moles × 342 g/mol = 1368 g
Hence, option B, 1368 g of sucrose, is the correct amount needed to prepare a 4 Osm solution in 1 liter of water.