Final answer:
The energy of one photon of light with a wavelength of 459 nm is 4.33 × 10^-19 J.
Step-by-step explanation:
The energy of one photon of light can be calculated using the equation E = hf, where E is the energy of the photon, h is Planck's constant (6.626 × 10-34 J·s), and f is the frequency of the light.
First, we need to find the frequency of the light using the equation f = c/λ, where c is the speed of light (3.00 × 108 m/s) and λ is the wavelength of the light (459 nm = 4.59 × 10-7 m).
Substituting the values into the equation, we get f = (3.00 × 108 m/s) / (4.59 × 10-7 m) = 6.53 × 1014 Hz.
Finally, we can calculate the energy of the photon using the equation E = (6.626 × 10-34 J·s) × (6.53 × 1014 Hz) = 4.33 × 10-19 J.