Question

Ammonium phosphate is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid with ammonia .

What mass of ammonium phosphate is produced by the reaction of 6.4g of ammonia without rounding any intermediate values?
Round your answer to 2 significant digits.

Answer 1

The mass of ammonium phosphate produced by the reaction of 6.4g of ammonia, rounded to two significant digits, is 25 g.

Step-by-step explanation:

To determine the mass of ammonium phosphate produced by the reaction of 6.4g of ammonia, we need to use stoichiometry based on the balanced chemical equation for the reaction:

2 NH3 + H3PO4 → (NH4)2HPO4

First, we convert the mass of ammonia to moles using its molar mass (17.03 g/mol):

6.4 g NH3 × (1 mol NH3 / 17.03 g) = 0.375 moles NH3

From the balanced equation, we see that 2 moles of ammonia react with 1 mole of phosphoric acid to produce 1 mole of ammonium phosphate.

Thus, in theory, 0.375 moles of NH3 would produce half that amount in moles of ammonium phosphate:

0.375 moles NH3 / 2 = 0.1875 moles (NH4)2HPO4

To find the mass of ammonium phosphate produced, we multiply the moles by its molar mass (132.06 g/mol):

0.1875 moles × 132.06 g/mol = 24.76 g of (NH4)2HPO4

Rounding to two significant digits, the mass of ammonium phosphate produced is 25 g.