Question

The path of a punted football is modeled by

16/1225 x^2+7/5+1.5
where f(x) is the height (in feet) and x is the horizontal distance (in feet) from the point at which the ball is punted.
(a) How high is the ball when it is punted?

Answer 1

1.5 feet

Explanation:

Given function,

→ f(x) = (-16/1225)x² + (7/5)x + 1.5

Required function,

→ f(x) = f(0)

→ f(0) = (-16/1225)x² + (7/5)x + 1.5

Now the needed height is,

→ (-16/1225)x² + (7/5)x + 1.5

→ (-16/1225)(0)² + (7/5)(0) + 1.5

→ 0 + 0 + 1.5

→ 1.5 feet

Hence, the height is 1.5 feet.

Answer 2

• (a) f(x) = 1.5 ft

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When the ball is punted the value of x is zero, therefore f(0) is:

• f(0) = - 16/1225 × 0² + 7/5 × 0 + 1.5 = 1.5