Question

A quantity x varies directly with the square of y and

inversely with the cube root of z. if x = 6 when y = 2
and z = 8, find the x when y = 1 and z = 27.​

Answer 1

x = 1

Explanation:

k is the constant of proportionality

Answer 2

• x = 1

-----------------------------

Given relation

• x = ky²/∛z, where k- constant

Given values

• x = 6, y = 2, z = 8

Find the value of k

• 6 = k×2²/∛8
• 6 = k×4/2
• 3 = k

The equation is now

• x = 3y²/∛z

Find the x when y = 1 and z = 27

• x = 3 × 1/∛27 = 3/3 = 1