Final answer:
The relaxed power of a myopic individual with a far point of 50 cm is 2 diopters (D), and with an 8% ability to accommodate, the nearest point for clear vision would be roughly 46.3 cm.
Step-by-step explanation:
Myopia, or nearsightedness, is a condition in which a person can see nearby objects clearly but has difficulty seeing objects far away. The power of an eye is the ability to focus light correctly on the retina to obtain a clear image. For a myopic administrator with a far point of 50.0 cm, the relaxed power of their eyes can be determined by using the formula P = 1/f, where f is the focal length in meters. In this case, the focal length is the maximum distance at which they can see clearly, 0.5 meters (50 cm). Therefore, the relaxed power would be P = 1/0.5 m = 2 diopters (D).
With a normal 8% ability to accommodate, the closest object they can see clearly is calculated considering the increase in diopters from relaxed to accommodated state. This normal accommodation suggests the eye's power can increase by 8% to help focus on closer objects. If the relaxed power is 2 D, an 8% increase is 0.16 D, making the accommodated power 2.16 D. The nearest point, or the closest distance for clear vision, can be found by taking the reciprocal of the accommodated power. Thus, the nearest point is approximately 1/2.16 D = 46.3 cm.