Answer:
She had 14 prescriptions for tranquilizers.
Explanation:
This question can be solved using a system of equations.
I am going to say that:
x is the number of prescriptions she had for antibiotics.
y is the number of prescriptions she had for tranquilizers.
A pharmacist found at the end of the day she had 3/2 as many prescriptions for antibiotics as tranquilizers.
This means that:
![(x)/(y) = (3)/(2)](https://img.qammunity.org/2022/formulas/mathematics/college/rm6wcmzy8eyq2pq3mb5be1c73ewn511ufm.png)
![x = (3y)/(2)](https://img.qammunity.org/2022/formulas/mathematics/college/z2mp9kexcpafnsfmguey9q9k1jzpnpgnl2.png)
She had 35 prescriptions altogether.
This means that:
![x + y = 35](https://img.qammunity.org/2022/formulas/mathematics/college/fm6wt7xnzqht9be6x5icusvuqhr7ibp6ud.png)
How many did she have for tranquilizers?
We want to find y. Since
, we solve the following equation.
![x + y = 35](https://img.qammunity.org/2022/formulas/mathematics/college/fm6wt7xnzqht9be6x5icusvuqhr7ibp6ud.png)
![(3y)/(2) + y = 35](https://img.qammunity.org/2022/formulas/mathematics/college/k5sheqave3j7gj6701ltz82py56ff8lmrf.png)
Multiplying everything by 2
![3y + 2y = 70](https://img.qammunity.org/2022/formulas/mathematics/college/uznewiy3zlfc7xjhlx1jnwjxcfbqyu7l72.png)
![5y = 70](https://img.qammunity.org/2022/formulas/mathematics/college/3jn2tbvjon0oxud7xlalfotdh8z0hgnfaf.png)
![y = (70)/(5)](https://img.qammunity.org/2022/formulas/mathematics/college/xqcv70owlsq8cadwbzfhwa41ju9xtefak6.png)
![y = 14](https://img.qammunity.org/2022/formulas/mathematics/college/rrtbeq20pmf8knc0qetrpdsz0rmdkq4lu5.png)
She had 14 prescriptions for tranquilizers.