Question

find the volume of metal required to make a closed box of thickness 1 cm with external measurements 12 cm × 7 cm × 10​

Answer 1

The volume of the metal is:

`V_(t)=548\: cm^(3)`

Explanation:

First, let's find the volume of the front face of the square:

`V_(1)=12*7*1=84\: cm^(3)`

The back face is the same, so we have:

`V_(2)=84\: cm^(3)`

The volume of the side faces will be:

`V_(3)=7*10*1=70\: cm^(3)`

`V_(4)=70\: cm^(3)`

And finally, the volume of the top and bottom side faces of the box will be:

`V_(5)=12*10*1=120\: cm^(3)`

`V_(6)=120\: cm^(3)`

The total volume of the metal will be:

`V_(t)=V_(1)+V_(2)+V_(3)+V_(4)+V_(5)+V_(6)`

`V_(t)=2(84)+2(70)+2(120)`

`V_(t)=548\: cm^(3)`

I hope it helps you!