Find the volume of metal required to make a closed box of thickness 1 cm with external measurements 12 cm × 7 cm × 10

Question

asked Jul 27, 2022 84.9k views

1 Answer

Jeromegamez · Answer 1 · 2022-08-02T23:30:18+0000

Answer:

The volume of the metal is:

$V_(t)=548\: cm^(3)$

Explanation:

First, let's find the volume of the front face of the square:

$V_(1)=12*7*1=84\: cm^(3)$

The back face is the same, so we have:

$V_(2)=84\: cm^(3)$

The volume of the side faces will be:

$V_(3)=7*10*1=70\: cm^(3)$

$V_(4)=70\: cm^(3)$

And finally, the volume of the top and bottom side faces of the box will be:

$V_(5)=12*10*1=120\: cm^(3)$

$V_(6)=120\: cm^(3)$

The total volume of the metal will be:

V_(t)=V_(1)+V_(2)+V_(3)+V_(4)+V_(5)+V_(6)

V_(t)=2(84)+2(70)+2(120)

$V_(t)=548\: cm^(3)$

I hope it helps you!