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Solve this .......,..,.,.,..,.,,.,.,.,.,.,.,.,.,..,.,.,.,.z.,.,.,.,..,.,.,.,.,,.,.,.,​

Solve this .......,..,.,.,..,.,,.,.,.,.,.,.,.,.,..,.,.,.,.z.,.,.,.,..,.,.,.,.,,.,.,.,​-example-1

1 Answer

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Answer: Molecular formula of copper (II) bromide is
CuBr_2

Molecular formula of aluminium (III) nitrate is
Al(NO_3)_3

Molecular formula of calcium (II) phosphate is
Ca_3(PO_4)_2

Molecular formula of iron (III) sulphide is
Fe_2S_3

Molecular formula of mercury (II) chloride is
HgCl_2

Molecular formula of magnesium (II) acetate is
(CH_3COO)_2Mg

Step-by-step explanation:

The name of the ionic compounds is written by writing the name of the cation first followed by its oxidation state in round brackets and then the name of the anion is written without any suffix. Thus the cation is written first followed by the oxidation state and then the anion.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral compound.

Molecular formula of copper (II) bromide is
CuBr_2

Molecular formula of aluminium (III) nitrate is
Al(NO_3)_3

Molecular formula of calcium (II) phosphate is
Ca_3(PO_4)_2

Molecular formula of iron (III) sulphide is
Fe_2S_3

Molecular formula of mercury (II) chloride is
HgCl_2

Molecular formula of magnesium (II) acetate is
(CH_3COO)_2Mg

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