Final answer:
The major product of adding water to propene using sulfuric acid as a catalyst is 2-propanol.
Step-by-step explanation:
The question pertains to predicting the major product of a chemical reaction involving hydration of an alkene using sulfuric acid (H2SO4) as a catalyst. When propene (CH3-CH=CH2) interacts with water and sulfuric acid, the most likely major product is 2-propanol (CH3CH(OH)CH3), which results from the addition of a hydroxyl group (OH) to the middle carbon atom in a Markovnikov manner due to the acid-catalyzed hydration of the double bond.
Example Reaction
For instance, the reaction between isobutylene (CH3CH=CHCH3) and water in the presence of a strong acid like H2SO4 can be shown as: CH3CH=CHCH3 + H2O → CH3CH(OH)CH2CH3. The product is tert-butyl alcohol.