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How much charge is needed to repel another charge of 9.9 x 10^-6 N when they are 200m apart? Please help meee I really can't understand Coulomb's Law : (

1 Answer

12 votes

Answer:

The charge needed will be
q=6.6\: \mu C

Explanation:

The equation of the electric force is given by:


F=k(qQ)/(r^(2))

We have the force
F = 9.9 10^(-6)\: N and the distance r = 200. k is the Coulomb constant. Q and q are the charges.

We assume we have the same charge of the particles, so we have:


q^(2)=(Fr^(2))/(k)


q^(2)=(9.9*10^(-6)200^(2))/(9*10^(9))


q=6.6*10^(-6)\: C

Therefore, the charge needed will be
q=6.6\: \mu C

I hope it helps you!

User Cesar Jr Rodriguez
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