Question

Find the equation of a line perpendicular to y=x+1 that passes through the point (−2,8).

Answer 1

y=-x+6

Explanation:

For linear graphs, the slope of perpendicular lines must be of equal value but opposite in sign: (
`m_1=-m_2`).

The slope of y=x+1 is 1, therefore the slope of the perpendicular line must be -1.

Given (x,y)=(-2,8) the equation of the perpendicular line can be obtained by substituting these values into the slope-intercept form y=mx+b.

8=(-1)(-2)+b

8=2+b

6=b

So, the perpendicular line has a slope-intercept form of y=-x+6 or y=6-x.