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Find the margin of error

Find the margin of error-example-1
User Jzadeh
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The margin of error for the proposed ban on high-capacity magazines in the image you provided is 10%. This means that if the poll were repeated multiple times, we could expect the results to vary by up to 10 percentage points in either direction.

The margin of error for the proposed ban on high-capacity magazines in the image provided is 10%. This means that we can be 95% confident that the actual proportion of American adults who support a ban on high-capacity magazines is between 59% and 79%. While this margin of error is relatively high, the fact that 69% of respondents support the ban suggests that there is a significant level of public support for this policy proposal.

To calculate the margin of error, we use the following formula:

Margin of error = ±√(p(1-p)/n)

where:

p is the proportion of respondents who support the proposed ban

n is the sample size

In this case, p = 0.69 and n = 852. Plugging these values into the formula, we get a margin of error of ±0.10, or 10%.

This means that we can be 95% confident that the actual proportion of American adults who support a ban on high-capacity magazines is between 59% and 79%.

User George Carrette
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