Final answer:
The average fluid velocity in a 3.00-cm-diameter pipe, when subject to a 0.500-T magnetic field that generates a 60.0-mV Hall voltage, is 4 meters per second.
Step-by-step explanation:
To determine the average fluid velocity in a 3.00-cm-diameter pipe when a 0.500-T magnetic field creates a 60.0-mV Hall voltage, we employ the Hall effect equation: E = B * v * d, where E is the Hall voltage (60.0 mV or 0.060 V), B is the magnetic field (0.500 T), v is the fluid velocity, and d is the depth of the fluid (which is the diameter of the pipe, 3.00 cm or 0.03 m). Rearranging the equation, v = E / (B * d), we get v = 0.060 V / (0.500 T * 0.03 m).
Now calculate the average fluid velocity v: v = 0.060 V / (0.500 T * 0.030 m) = 0.060 V / 0.015 T*m = 4 m/s. Thus, the average fluid velocity is 4 meters per second.