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Y=x(4)/2+3x(3)-2x-12

Y=x(4)/2+3x(3)-2x-12-example-1
User Ipj
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1 Answer

9 votes

Answer:


\displaystyle y' = -2x^3 + 9x^2 - 2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Terms/Coefficients

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Explanation:

Step 1: Define


\displaystyle y = -(x^4)/(2) + 3x^3 - 2x - 12

Step 2: Differentiate

  1. Basic Power Rule:
    \displaystyle y' = -(4x^(4 - 1))/(2) + 3 \cdot 3x^(3 - 1) - 1 \cdot 2x^(1 - 1)
  2. Simplify Exponents:
    \displaystyle y' = -(4x^3)/(2) + 3 \cdot 3x^2 - 1 \cdot 2
  3. Divide:
    \displaystyle y' = -2x^3 + 3 \cdot 3x^2 - 1 \cdot 2
  4. Multiply:
    \displaystyle y' = -2x^3 + 9x^2 - 2
User Ardabro
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