Question

URGENT HELP !! The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively. How much horizontal force would you need to apply to a 34.4 kg object to start it moving from rest?

Answer 1

43.83 N

Step-by-step explanation:

Given that,

The mass of an object, m = 34.4 kg

The coefficients of static and kinetic frictions for plastic on wood are 0.53 and 0.40, respectively.

The force of static friction,

`F_s=\mu_smg\\\\F_s=0.53* 34.4* 9.8\\\\F_s=178.67\ N`

The force of kinetic friction,

`F_k=\mu_kmg\\\\F_k=0.40* 34.4* 9.8\\\\F_k=134.84\ N`

Net force acting on the object is :

F = 178.67-134.84

= 43.83 N

Hence, this is the required solution.