Question

Simplify:

4(r + 1) + 3r

A. 4r + 4
B. 5r + 1
C. 7r + 1
D. 7r + 4

Answer 1

the correct answer is , D. 7r + 4
using the pemdas method will result in the correct answer .

1. distribute 4 to r and 1
•4r and 4 (4r + 4)
2. combine like terms
•4r and 3r (4r+3r)
3. add like terms together
•4r + 3r = 7r
4. since our constant from step one has no other like terms , it stays as is resulting in our answer being : D. 7r + 4

Answer 2

look in the explanation, it is in there

Explanation:

i don't know if you are distributing or just using PEMDAS .

if you are distributing then: do in the equation 4(r + 1) + 3r.. do 4 x r and 4 x 1 , now you have 4r + 4 + 3r

7r +4

is what i got!

If you are doing PEMDAS then: first you do what is inside the perenthisis ()

4(r + 1) +3r changes into

4( r1 ) + 3r now you do multipulcation because that in the "M" in pemdas

4r + 3r, then if you are using like terms you would add them

7r

i hope this helps you out!