Question

a 7.00 kg mass and a 4.00 kg mass are mounted on a spindle that is free to turn about the x axis as shown. Assume the mass of the arms as shown. Assume the mass of the arms and the spindle to be negligible. the gravitational acerlation is 9.81 m/s^s and the lever length is r2=3m then r1=5m*cos37

Answer 1

The force the wheelbarrow exerts on the ground is -441.45 N.

In this problem, we have a wheelbarrow with a load and hands supporting it. The load has a perpendicular lever arm of 7.50 cm, while the hands have a perpendicular lever arm of 1.02 m.

We need to find the upward force required to support the wheelbarrow and its load if their combined mass is 45.0 kg and the force the wheelbarrow exerts on the ground.

(a) To find the upward force, we can use the equation: Force = mass * (gravitational acceleration + angular acceleration * perpendicular lever arm).

Substituting the given values, Force = 45.0 kg * (9.81 m/s^2 + 0). Therefore, the upward force required to support the wheelbarrow and its load is 45.0 kg * 9.81 m/s^2 = 441.45 N.

(b) To find the force the wheelbarrow exerts on the ground, we can use Newton's third law: Force on the ground = -Force on the hands. Therefore, the force the wheelbarrow exerts on the ground is -441.45 N.