Final answer:
The magnitude of the buoyant force experienced by the cylindrical object is approximately 92.12 N.
Step-by-step explanation:
The magnitude of the buoyant force experienced by the cylindrical object can be calculated using Archimedes' principle. According to this principle, the buoyant force is equal to the weight of the water displaced by the object. The weight of water displaced is given by the formula Ww = mwg, where m is the mass of the water displaced, g is the acceleration due to gravity (approximately 9.8 m/s²), and w is the density of water (approximately 1000 kg/m³).
In this case, the cylindrical object is completely submerged in water, so its entire volume is displacing water. The volume of a cylinder is given by the formula V = πr²h, where r is the radius and h is the height. Plugging in the values r = 0.1 m and h = 0.3 m, we can calculate the magnitude of the buoyant force:
V = π(0.1 m)²(0.3 m) = 0.0094 m³
m = wV = (1000 kg/m³)(0.0094 m³) = 9.4 kg
Ww = mwg = (9.4 kg)(9.8 m/s²) = 92.12 N
Therefore, the magnitude of the buoyant force experienced by the object is approximately 92.12 N.