Answer:
The maximum possible up-thrust on the boat is 11,995.2 N
Step-by-step explanation:
According to Archimedes' principle, the thrust received by an object immersed a fluid is equal to the weight of the fluid displaced;
The given parameter of the boat in sea water are;
The volume of the boat = 1.2 m³
The density of seawater = 1020 kg/m³
Density = Mass/Volume
Therefore, Mass = Density × Volume
The maximum volume of water that the boat displaces = 1.2 m³
The mass of the water displaced by the boat = (Density of seawater) × (Volume of seawater displaced)
∴ The maximum possible mass of the water displaced by the boat = 1.2 m³ × 1020 kg/m³ = 1224 kg
The maximum possible mass of the water displaced by the boat, m = 1224 kg
Weight = Mass, m × g
Where;
g = The acceleration due to gravity = 9.8 m/s²
The up-thrust on the boat = The weight of the seawater displaced
∴ The maximum possible up-thrust on the boat = m × g = 1224 kg × 9.8 m/s² = 11,995.2 N
The maximum possible up-thrust on the boat = 11,995.2 N.