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If a sphere has the same volume as a cube with edge length 5, estimate the radius of the sphere.

User CervEd
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Sphere's radius: approximately 3.1 units, matching volume with a cube of edge length 5 units.

The volume of a cube with edge length 5 is calculated using the formula for the volume of a cube:
\(V_{\text{cube}} = \text{side}^3 = 5^3 = 125 \text{ cubic units}\).

For a sphere, the volume formula is
\(V_{\text{sphere}} = (4)/(3) \pi r^3\), where r is the radius of the sphere. We're looking for a sphere with the same volume as the cube, which is 125 cubic units.

Setting up the equation
\(125 = (4)/(3) \pi r^3\), we can solve for the radius \(r\).

First, rearrange the equation to solve for r³:


\((4)/(3) \pi r^3 = 125\)\\\(r^3 = (125 * 3)/(4 \pi)\)\\\(r^3 = (375)/(4 \pi)\)

Now, solve for r by taking the cube root of both sides:


\(r = \sqrt[3]{(375)/(4 \pi)}\)

Approximately:


\(r \approx \sqrt[3]{(375)/(4 \pi)} \approx \sqrt[3]{(375)/(4 * 3.14)} \approx \sqrt[3]{(375)/(12.56)} \approx \sqrt[3]{29.85}\)


\(r \approx 3.1\) (rounded to one decimal place)

Hence, the estimated radius of the sphere, which has the same volume as a cube with an edge length of 5, is approximately 3.1 units.

User Avriis
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