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Subtract ​ 12y^2 − 8y + 3 ​ from 3y^2 − 15 y+ 14.l simplify completely

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Final answer:

To subtract 12y^2 - 8y + 3 from 3y^2 - 15y + 14, reverse the signs of the second polynomial and combine like terms, resulting in 15y^2 - 7y + 17.

Step-by-step explanation:

To subtract the polynomial 12y2 − 8y + 3 from 3y2 − 15y + 14, we need to first reverse the sign of each term in the polynomial 12y2 − 8y + 3 because we are subtracting it. The reversed terms will be −12y2, +8y, −3.

Step-by-step subtraction:

  1. Start with the first polynomial: 3y2 − 15y + 14.
  2. Subtract the second polynomial with reversed signs: −12y2 (+12y2), +8y(−8y), −3(+3).
  3. Combine like terms:
  4. The result of the subtraction is 15y2 − 7y + 17.

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