Final answer:
To subtract 12y^2 - 8y + 3 from 3y^2 - 15y + 14, reverse the signs of the second polynomial and combine like terms, resulting in 15y^2 - 7y + 17.
Step-by-step explanation:
To subtract the polynomial 12y2 − 8y + 3 from 3y2 − 15y + 14, we need to first reverse the sign of each term in the polynomial 12y2 − 8y + 3 because we are subtracting it. The reversed terms will be −12y2, +8y, −3.
Step-by-step subtraction:
- Start with the first polynomial: 3y2 − 15y + 14.
- Subtract the second polynomial with reversed signs: −12y2 (+12y2), +8y(−8y), −3(+3).
- Combine like terms:
- The result of the subtraction is 15y2 − 7y + 17.