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If x=6 and y=2 then the value of 3x^2-4(2y-4/12) +8

User Slavic
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1 Answer

6 votes

Answer:

3x^2−8y+28/3

Explanation:

3x^2-4(2y-4/12) +8

Reduce the fraction 4/12 to lowest terms by extracting and canceling out 4.

3x^2-4(2y-1/3) +8

Use the distributive property to multiply −4 by 2y - 1/3

3x^2-8y+4/3+8

Add 4/3 and 8 to get 28/3

3x^2−8y+28/3

User Laurenzlong
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