Final answer:
Using Archimedes' principle, the weight of the water on the diving bell at maximum depth is the buoyant force and is found by multiplying the mass of the water displaced by the acceleration due to gravity. The correct formula is W = P x V, resulting in a weight of 9.80 x 10¸ N.
Step-by-step explanation:
The student's question involves calculating the weight of the water on the top of the experimental diving bell while at maximum depth. To find the weight of the water displaced by the diving bell, also known as the buoyant force, we use Archimedes' principle. This principle states that the buoyant force is equal to the weight of the water displaced by the submerged object.
The formula to use in this case would be W = m x g, where W is the weight, m is the mass of the water displaced, and g is the acceleration due to gravity. Given that the density (Pw) of water is 1.000 x 10³ kg/m³ and the maximum volume (Vw) of water the bell can displace is 1.00 x 10µ m³, we can calculate the mass of the water displaced: m = Pw x Vw = 1.00 x 10³ kg/m³ x 1.00 x 10µ m³ = 1.00 x 10¸ kg. Thus, the maximum buoyant force, which is also the weight of this volume of water, is m x g = 1.00 x 10¸ kg x 9.80 m/s² = 9.80 x 10¸ N. Hence, option D, W = P x V, is the correct formula to calculate the weight of the water on the top of the diving bell when it is at maximum depth.