Question

How much heat is transferred when during a reaction, 531 g of water increases from 22.7 ○C to 38.8 ○C?

Answer 1

8.55 × 10³ cal

Step-by-step explanation:

Step 1: Given and required data

• Mass of water (m): 531 g

• Specific heat of water (c): 1 cal/g.°C

• Initial temperature: 22.7 °C

• Final temperature: 38.8 °C

Step 2: Calculate the temperature change (ΔT)

ΔT = Final temperature - Initial temperature = 38.8 °C - 22.7 °C = 16.1 °C

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 1 cal/g.°C × 531 g × 16.1 °C = 8.55 × 10³ cal